Published by:
CGP EDU Academic Team
Published on: August 13, 2026
In a vessel, two equilibrium are simultaneously established at the same temperature as follows:
N 2 (g) + 3H 2 (g) 
2 NH 3 (g) ...
A
N 2 (g) + 2H 2 (g) 
N 2 H 4 (g) ...
N 2 H 4 (g) ...
B
Initially the vessel contains N 2 and H 2 in the molar ratio of 9 : 13. The equilibrium pressure is 7P 0 , in which pressure due to ammonia is P 0 and due to hydrogen is 2P 0 . Find the values of equilibrium constants (K P ’s) for both the reactions
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
( 
= 
, 
= 
)
N 2 (g) + 3H 2 (g) 
2NH 3 (g)
9P – x – y 13P – 3x – 2Y 2x
N 2 (g) + 2H 2 (g) 
N 2 H 4 (g)
9P – x – y 13p – 3x – 2Y Y
given 9P – x – y + 13P – 3x –2y + 2x + y = 7P o
22P – 2x – 2y = 7P o ........
then 2x = P o ..........
and 13P – 3x – 2y = 2P o .........
P = 
9P – x – y = 
– 
– 
= 
2y = 
P o = 3P o
13P – 3x – 2y = 
– 
– 
= 2P o y = 
P o
K 1 = 
= 
= 
K 2 = 
= 
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